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Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride. Select the correct answer from above options

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Correct Answer - 0.458,0542 WC6H6=30g,Wsol=100g,WCCl4=(100-30)g =70g Mw of C6H6=78gmol-1,MwofCCl4=12+4×35.5 =154gmol-1 nC6H6= WC6H6 Mwofc6H6 = 30g 78gmol-1 =0.385 nCCl4= WCCl4 MwofCCl4 = 70g 154gmol-1 =0.425 CHMiC6H6= nC6H6 nC6H6+nCCl4 = 0.385 0.385+0.425 = 0.385 0.84 =0.485 CHMiCCl4=1-0.485=0.542

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