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Calculate the (a) molality, (b) molartiy, and (c) mole fraction of KI if the density of 20%( mass / mass ) aqueous KI is 1.202gmL-1 . Select the correct answer from above options

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Correct Answer - a.1.5molkg-1 b.1.448M c.0.0263 W2=20g,Wsol=100g W1=100-20=80g m= W2×1000 Mw2×W1 = 20×1000 166×80 =1.5molKg-1 b. Mw2 of Kl=39+127=166gmol-1 M+ %bymass×10×dsol Mw2 = 20×10×1.202 166 =1.448M c. CHMi2= n2 n1+n2 = W2/Mw2 W1/Mw1+W2/Mw2 20/166 80/18+20/166 = 0.12 4.44+0.12 = 0.12 4.56 =0.0263

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