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Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving `1.0g` of polymer of molar mass `185,000` in `450mL` of water a

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Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0g of polymer of molar mass 185,000 in 450mL of water at 37∘C . Select the correct answer from above options

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Correct Answer - 30.96Pa W2=1.0g,Mw2=185000gmol-1 T=37∘C=37+273=310K R=8.314KPaLK-1mol-1 =8.314×103PaLK-1mol-1 V=450mL=0.450L, osmotic pressure (π)=? n2= W2 Mw2 = 1.0g 185,000gmol-1 = 1 185000 mol Applying the formula , we get π=MRT= n2 V(inL) ×RT = 1 185000×0.450L ×8.314103PaLK-1mol-1×310K ltbr. =30.96Pa

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