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The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M K

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The resistance of a conductivity cell contaning 0.001MKCl solution at 298K is 1500Ω . What is the cell constant if conductivity of 0.001MKCl solution at 298K is 0.146×10-3Scm-3Scm-1 . Select the correct answer from above options

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Correct Answer - 0.219cm-1 Cell constant (G∗)= Conductivity(k) Conductance(G) =k×R =0.146×10-3Scm-1×1500ohm =0.219cm-1

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