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A reaction is second order with respect to a reaction. How is the rate of reaction affected if the (a) doubled, (b) reduced to 1/2 ? Select the correct answer from above options

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Correct Answer - a. Rate becomes 4 times. b. Rate becomes 1/4 times. R→PorA→B a. Rate=r1=k[A]2 r2=k[2A]2 r2=4r1 Rate becomes 4 times. b. r1=k[A]2 r2=k[ 1 2 A]2 r2 r1 =[ 1 2 ]2⇒r2= 1 4 r1 Hence, rates becomes 1 4 times.

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