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The rate constant for a first order reaction is 60s-1 . How much time will it take to reduce the initial concentrationof the reactant to its 1/16th value ? Select the correct answer from above options

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Correct Answer - 4.6×10-2s k= 2.303 t log a a-x a=1M,a-x= 1 16 M,k=60s-1 t= 2.303 60 log 1 1 =0.03838×log16 =0.03838×1.2041 =4.6×10-2s

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