Correct Answer - Ea=52.8mol-1
Let k
at 293K=k1,kat313K=k2
∴k2=4k1or
k2
k1
=4
Using Arrhenius equation,
log
k2
k1
=
Ea
2.303R
(
T2-T1
T1T2
)
log4=
Ea
2.303×8.314JK-1mol-1
×
(313-293)
313×293
0.606=
Ea
2.303×8.314
×
10
313×293
Solvie for Ea:
∴Ea=52860Jmol-1=52.86mol-1