An alkene "A" on reaction with `O_3` and Zn gives propanone and ethanol in equimolar Addition of HCl to alkene "A" gives "B" as the product. The struc

Question

An alkene "A" on reaction with O 3 O and Zn gives propanone and ethanol in equimolar Addition of HCl to alkene "A" gives "B" as the product. The structure of product "B" is: A. H 3 C − C H ∣ C l − C H 3 ∣ C H ∣ C H 3 H B. C l − C H 2 − C H 2 − C H 3 ∣ C H ∣ C H 3 C C. D. H 3 C − C H 2 − C H 3 ∣ C ∣ C l − C H 3 H Select the correct answer from above options

Answer 1

Correct Answer - D A = C H 3 − C ∣ C H 3 = C H − C H 3 A B = C H 3 − C l ∣ C ∣ C H 3 − C H 2 − C H 3 B Formation of B from A is markonikoff rule addition by E.A.R mechanism