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For a cell involving one electron E 0 c e l l = 0.59 V E and 298K, the equilibrium constant for the cell reaction is: [Given that 2.303 R T F = 0.059 V 2.303 at T = 298 K T ] A. 1.0 × 10 30 1.0 B. 1.0 × 10 2 1.0 C. 1.0 × 10 5 1.0 D. 1.0 × 10 10 1.0 Select the correct answer from above options

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Correct Answer - D Nearest equation E ɵ c e l l = E ɵ c e l l − 0.059 n log Q C E At equilibrium Ecell = 0 , Q C = K C = E ɵ c e l l = − 0.059 n log K C Value of E ɵ c e l l = 0.59 V E 0.59 = 0.059 1 log K C value of n = 1 0.59 K C = antilog 10 K K C = 1 × 10 10 K

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