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What is the probability that there will be 53 Mondays in a randomly selected leap year? Select the correct answer from above options

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Every year has 52 complete weeks 8 = 364 days (52 × 7) A leap year has 366 days, in the remaining two days we have to see what is the probability I getting Monday, the two days may occur in any one of the following (Sunday, Monday) (Mon,Tue), (Wed, Thur) (Thur,Fri) (Fri, Satur) (Satur, Sun) Out of the 7 Possibilities, the first two cases have Monday ∴ P(53Mondays in a leap) = \(\frac{2}{7}\)

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