Totally there are 52 cards and any one can be drawn
∴ Total no cases = n = 52
(a) There are 26 black cards and 2 jack totally = 28 cards
∴ no of favourable case = m = 28
∴ P(black or jack) = \(\frac{28}{52}\)
(b) There are 26 red cards
∴ m = 26,
(C) There are 13 diamonds cards
∴ m = 13,
P(getting diamond) = \(\frac{13}{52} = \frac{1}{4}\)