Question

Two coins are tossed simultaneously 500 times with the following frequencies of different outcomes: Two heads: 95 times One tail: 290 times No head : 115 times Find the probability of occurrence of each of these events. Select the correct answer from above options

Answer 1

We know that, Probability of any event = (Number of favorable outcome) / (Total number of trials) Total number of trials = 95 + 290 + 115 = 500 Now, P(Getting two heads) = \(\frac{95}{500}\) = 0.19 P(Getting one tail) = \(\frac{290}{500}\) = 0.58 P(Getting no head) = \(\frac{115}{500}\) = 0.23