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In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that on a ball played: (i) He hits boundary (ii) He does not hit a boundary. Select the correct answer from above options

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Total number of balls played by a player = 30 Number of times he hits a boundary = 6 Number of times he does not hit a boundary = 30 – 6 = 24 We know, Probability of an event = (Number of Favorable outcomes) / (Total Numbers of outcomes) Now, (i) Probability (he hits boundary) = (Number of times he hit a boundary) / (Total number of balls he played) = \(\frac{6}{30}\) = \(\frac{1}{5}\) (ii) Probability that the batsman does not hit a boundary = \(\frac{24}{30}\) = \(\frac{4}{5}\)

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