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Given two independent events A and B such that P (A) = 0.3, P (B) = 0.6. Find (i) P (A and B) (ii) P (A and not B)

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Given two independent events A and B such that P (A) = 0.3, P (B) = 0.6. Find (i) P (A and B) (ii) P (A and not B) (iii) P (A or B) (iv) P (neither A nor B) Select the correct answer from above options

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(i) i.e. P (A∩B) = P (A) x P (B) = .3 x .6 = .18 (ii) P(A and not B) = = P(A) x ⇒ P (A) x [1-P(B)] = .3 x (1 – 0.6) = .3 x .4 = .12 (iii) P(A or B) = P(A∪ B) = P(A) + P(B) – P(A∩B) = .3+ .6-.18 = .9 -.18 = .72 (iv) P(neither A nor B)

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