Here n(s) = (6 + 4. 2)C, = 12C1,
(a) Let A:both are red ⇒ n(A)= 6C2
(b) Let B: 1 white & 1 Black
(c) Let C1: Both are of same colour.
n(c) = 4c2 or 2C1 = 15 + 6 + 1 = 22
(d) Let D both are of different colour no of selections
6C1 x 4C1 or 4C1 x 2C or 6C1 x 2C1 = 24 + 8 + 12 = 44