We know that a die has 6 spaces
Sample space S = {1, 2, 3, 4, 5, 6}
Total no. of outcomes = 6
Consider P (A) as the probability of getting an even number
So the sample space A = {2, 4, 6}
P (A) = 3/6 = 1/2
Consider P (B) as the probability of getting a number whose value is greater than 2
So the sample space B = {3, 4, 5, 6}
(A ∩ B) = {4, 6}
We get
P (A ∩ B) = 2/6 = 1/3
Here the probability of getting a number greater than 2 given that the outcomes is even is written as
