Answer : (c)
24
29
Let,
E1: Examinee guesses the answer
E2: Examinee copies the answer
E3: Examinee knows the answer
E : Event examinee answers correctly
Given, P(E1) =
1
3
, P(E2) =
1
6
∴ P(E3) = 1 – (P(E1) + P(E3)) = 1- (
1
3
+
1
6
) =
1
2
Given, P(E/E1)=
1
4
,P(E/E2)=
1
8
,P(E/E3)=1
∴ Required probability = P(E3/E)
=
P(E3).P(E/E3)
P(E1).P(E/E1)+P(E2).P(E/E2)+P(E3).P(E/E3)
=
1
2
.1
1
3
×
1
4
+
1
6
×
1
8
+
1
2
×1
=
1
2
1
12
+
1
48
+
1
2
=
1
2
4+1+24
48
=
1
2
29
48
=
24
29