Total number of cases, `n(S) =" Area of rectangle"`
` " "=3xx 2 = 6m^(2)`
Favourable number of cases, `n(E) = "Area of circle" = pi ((1)/(2))^(2)= (pi)/(4)m^(2)" "(because "diameter = 1 rArr "radisu" =(1)/(2))`
`therefore ` Probability that the die land inside the circle `= (n(E))/(n(S)) = (pi//4)/(6) = (pi)/(24)`