Given - A and B be the events such that P(A) = \(\frac{7}{13}\), P(B) = \(\frac{9}{13}\) and P(A ∩ B) = \(\frac{4}{13}\)
To find –
(i) P(A/B)
(ii) P(B/A)
(iii) P(A \(\cup\) B)
(iv) \(P(\overline B/ \overline A)\)
Formula to be used – By conditional probability, P(A/B) = \(\frac{P(A\cap B)}{P(B)}\) where P(A/B) is the probability of occurrence of the event
A given that B has already occurred.
.
= \(\frac{1}{6}\)