Two die having 6 faces each when tossed simultaneously will have a total outcome of 62 = 36
Let P(A) be the probability of getting a sum equal to 5.
Let P(B) be the probability of getting 2 different numbers.
Probability of getting 2 different numbers
= 1 – probability of getting same numbers
= 1 – 1/6
= 5/6
\(\therefore P(B)=\frac{5}{6}\)
Let P(A ∩ B) = be the probability of getting a sum = 5 and two different numbers at the same time.
The sample space of (A ∩ B) = {(1,4),(2,3),(3,2),(4,1)}
Tip – By conditional probability, P(A/B) = \(\frac{P(A \cap B)}{P(B)}\) where P(A/B) is the probability of occurrence of the event
A given that B has already occurred.
The probability that the sum = 5 given that two different numbers were thrown:
