Correct Answer - B
One integer can be chosen out of 200 integers in .200C1
ways.
Let A be the event that an integer selected is divisible by 6 and B that it is divisible by 8. Then,
P(A)=
33
200
,P(B)=
25
200
and P(A∩B)=
8
192
∴
Required probability =P(A∪B)
=P(A)+P(B)-P(A∩B)
=
33
200
+
25
200
-
8
192
=
1
4