Question

A die is thrown three times, find the probability that 4 appears on the third toss if it is given that 6 and 5 appear respectively on first two tosses. Select the correct answer from above options

Answer 1

Here, `A = `Event that `6` and `5` appears on first two tosses. It means third toss can have any of the six values. `:. n(A) = 6` Let `B = `Event that `4` appears on the third toss. Now, `(AnnB) = {(6,5,4)}` `=>n(AnnB) = 1` `:.` Required probability , `P(B/A) = (n(AnnB) )/(n(A)) = 1/6.`