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Bag I contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it

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Bag I contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it was drawn from Bag II. Select the correct answer from above options

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A= taking red ball B=selecting a Ball `P(B_1)=P(B_2)=1/2` `P(A/B_1)=3/7` and `P(A/B_2)=5/11` `P(B_2/A)=(P(A/B_2)P(B_2))/(P(A/B_2)P(B_2)+P(A/B_1)P(B_1))` `P(B_2/A)=((5/11)(1/2))/((5/11)(1/2)+(3/7)(1/2))` =`35/68`.

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