Question

An electric field is given as E = 6y^2z i + 12xyz j + 6xy^2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule) (a) 0.64 (b) 0.72 (c) 0.78 (d) 0.80 The question was asked by my school teacher while I was bunking the class. This question is from Line Integral topic in section Vector Calculus of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

The correct option is (b) 0.72 Easy explanation: W = -Q E.dl W = -2 X 10^-3 X (6y^2z i + 12xyz j + 6xy^2 k) . (-3 i + 5 j -2 k) At p(0,2,5), W = -2(-18.22.5) X 10^-3 = 0.72 J.