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The conductivity of a material with current density 1 unit and electric field 200 μV is (a) 2000 (b) 3000 (c) 4000 (d) 5000 This question was posed to me during a job interview. This intriguing question originated from Stokes Theorem topic in portion Vector Calculus of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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The correct choice is (d) 5000 The explanation is: The current density is given by, J = σE. To find conductivity, σ = J/E = 1/200 X 10^-6 = 5000.

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