Question

Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ) (a) 3.16 (b) 5.16 (c) 7.16 (d) 9.16 I got this question in an international level competition. The doubt is from Electrostatic Energy topic in portion Electrostatic Fields of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

Correct option is (a) 3.16 Easy explanation: The energy in an electric field is given by, W = 0.5 x D x E. Since D = εE, we get W = 0.5 x ε x E^2. On substituting the data, we get 3.16 microjoule.