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Find the electric field of a potential function given by 20 log x + y at the point (1,1,0). (a) -20 i – j (b) -i -20 j (c) i + j (d) (i + j)/20 This question was addressed to me in exam. The doubt is from Poisson and Laplace Equation topic in section Electrostatic Boundary Value Problem of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Correct option is (a) -20 i – j The explanation: The electric field is given by E = -Grad(V). The gradient of the given function is 20i/x + j. At the point (1,1,0), we get 20i + j. The electric field E = -(20i + j) = -20i – j.

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