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Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A. (a) 250 (b) 325 (c) 175 (d) 375 The question was asked in an interview for job. The query is from Magnetic Field Intensity topic in section Magnetostics of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right option is (d) 375 Easiest explanation: The magnetic field intensity of a solenoid is given by H = NI/L = 30 X 1.5/0.12 = 375 units.

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