Consider a circuit consisting of two capacitors C1 and C2. Let R be the resistance and L be the inductance which are connected in series. Let Q1 and Q2 be the quality factor for the two capacitors. While measuring the Q value by the Parallel Connection method, the value of the Q factor is?
(a) Q = \frac{(C_1 – C_2) Q_1 Q_2}{Q_1 C_1-Q_2 C_2}
(b) Q = \frac{(C_2 – C_1) Q_1 Q_2}{Q_1 C_1-Q_2 C_2}
(c) Q = \frac{(C_1 – C_2) Q_1 Q_2}{Q_2 C_2-Q_1 C_1}
(d) Q = \frac{(C_2 – C_1) C_1 C_2}{Q_1 C_1-Q_2 C_2}
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