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Determine the value of Z22 in the circuit shown below.

(a) 0

(b) 1

(c) 2

(d) 3

This question was addressed to me in class test.

Query is from Open Circuit Impedence(Z) Parameters in section Two-Port Networks of Network Theory

Select the correct answer from above options

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1 Answer

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The correct choice is (c) 2

For explanation I would say: Open circuiting port 1, we get V2 = I2((2+2)||4) => V2 = I2 x 2 => V2/I2 = 2. Therefore the value of Z22 is 2Ω.